0=(12-3x^2)/4

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Solution for 0=(12-3x^2)/4 equation: 


x in (-oo:+oo)

0 = (12-(3*x^2))/4 // - (12-(3*x^2))/4

0-((12-(3*x^2))/4) = 0

-((12-3*x^2)/4) = 0

(-1*(12-3*x^2))/4 = 0

( -1 )

-1 = 0

x belongs to the empty set

( 12-3*x^2 )

-3*x^2 = -12 // : -3

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { 2, -2 }

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